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Advanced Placement Companion: Precalculus
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Portable Network Graphic
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1998-03-12
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ocr:
Then, we reassociate the matrices. I -5/11 -1/22 -7/221 1-3 X - (4-44)x-A-1B- 2/11 7/22 5/22 - : 2 - - 1 - ENe N - 1 1/2 1/2 4 -5/11 -1/22 -7/221-9 - - - à - LF 2/11 7/22 1/2 5/22 - JL - 11 - - 5 1 1/2 - 45_11+-35 1001 X 11 - 22 22 x 21 Multiply 010 . - y 11 -18177+25 22 - 22 . or - - GE - 00112 -9+11+5 ZJ 2 2 The solution is (2,3,-1). Solving a3 x3 System by Using an Inverse Matrix